Date: 07-11-12 16:58
LiTE: Liangís Theory of Everything.
Part 4.3 What are forces. Sepcon forces.
In the last part I had explained that a sepcon is made of a combination of a positive electric force and a negative electric force. In other words a sepcon matter unit is made of a combination of a negative electric force message unit of an electron and a positive electric force message unit of a proton. Since these two message units contain opposing messages and data it can be expected that a matter unit created out of a combination of these two opposing forces will emit force message units that would alternatively act like a negative electric force and a positive electric force. To illustrate this I will give an analogous example using two sorting subroutines of a computer program.
One of the subroutines sort by comparing two numbers and push the bigger one to the back or lower down. Suppose the input consist of 10 numbers 1 to 10 arranged randomly. Then after 9 comparisons the biggest number or 10 will be placed in the bottom-most or rear-most position. Then another 9 comparisons (or 8) can be done which will result in the second largest number or 9 being put in the second position from the bottom or from the rear. After 9 iterations the 10 numbers will be arranged in ascending order.
The other subroutine does the opposite and push the smaller number to the back after each comparison. And after 9 iterations result in sorting the 10 numbers in descending order. Imagine the computer program written on computer cards like 30 or 40 years ago and somebody dropped the box of cards and the two subroutines got mixed together. If we run this program (obviously it will probably not even compile but just imagine it will) we can imagine the output not to be in perfect ascending order or perfect descending order. If we sort 10 sets of 10 random numbers the output may vary from set to set. For example, the first set of 10 random numbers might be sorted in perfect ascending order:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Then the second set may be sorted so that 8 of the numbers are sorted in ascending order while the last two numbers are sorted in descending order such as:
2, 1, 3, 4, 5, 6, 7, 8, 9, 10.
And the third set got sorted as:
3, 2, 1, 4, 5, 6, 7, 8, 9, 10.
And so on until the last set being sorted in perfect descending order:
10, 9, 8, 7, 6, 5, 4, 3, 2, 1.
So what is the point of this example? The point is that when two messages are delivered or two tasks are performed and if they are somehow combined then the resulting message or outcome might be expected to vary over the range between the two original messages or tasks. Therefore, it can be expected that it will act like either in a cyclical manner, first acting like one and then acting like the other or something in between. The sepcon is made out of a combination of two opposing electric forces - a positive electric force message unit and a negative electric force message unit. Therefore, the sepcon force can be expected to act first like a positive electric force and be repulsive against the proton and then act like a negative electric force and be attractive to it.
The sepcon matter units themselves do not perform the task of delivering messages to the protons and electrons. After the sepcon disk is formed, each sepcon matter unit emits a sepcon force message unit which carries the message to the proton and electron. But the sepcon matter units donít have the essential ability or programming to produce message units by themselves. Only when a positive or negative electric force message unit hits it, can the sepcon matter unit then transform the electric force message unit giving it a different kind of message to carry and then project it outward. The altered message carried by sepcon force message units as they move out from the proton side of the sepcon disk will alternately repulse the proton and then attract it while on the other side of the sepcon disk the sepcon force message units will alternately repulse the electron and then attract it.
Imagine an X-axis. Place the electron at X=0 and the proton at X=2. Draw a circle with its center at the electron or at X=0 and radius r1=2^0.5 (square root of 2); let the point X=2^0.5 be designated as P1. Draw another circle with its center at X=2 and radius r=2^0.5. The overlapping area is the sepcon disk. Of course, instead of two circles it should really be two spheres where the intersection of the two spheres form a 3-dimensional disk with its center on the line joining the electron and proton. Designate the sphere with its center at the electron or X=0 and r=2^0.5 as S1.
Now draw another circle or imagine another sphere with its center at the electron and radius r2=2=(2^0.5)^2. Designate this sphere as S2. The hemispherical region on the proton side between these two spheres, S1 and S2, is the repulsive region and designate it as R1 or Repulsive region 1. The sepcon message units in this region of space, R1, will deliver the message to move the proton away from the sepcon surface. That is, the sepcon force message unit will repulse the proton anywhere inside the region of space R1.
Now draw another circle or imagine another sphere with its center at the electron or X=0 and radius r3=2.8284=(2^0.5)^3. Designate this sphere as S3. Inside the hemispherical region on the proton side between the spheres S2 and S3, call it A1 or Attractive region 1, the sepcon force will be attractive. That is, the proton inside region A1 will be attracted toward the sepcon.
Let the strength of the force be 1 at r1=2^0.5. Therefore, the strength of the force at r2=2 is 0.5; and the strength of the force at r3=2.8284 is 0.25.
Imagine the sepcon force message unit to be an earth with a line running from the south pole through the north pole and extended out infinitely. The earth moves northward along this line (but does not spin around this line). Imagine the proton as a meteor that hits the earth, passes through the center and out the other side. As the meteor passes through the center of the earth a force is applied to it in some direction. The strength and direction of the force is determined by the number of times the sepcon force has split (or indirectly by the distance it has traveled from the surface of the sepcon disk).
The surface of the sepcon disk on the proton side is located at X=2^0.5. Each matter unit of the sepcon disk modifies a unit of positive electric force that impacts it by changing the message it carries and projects it outward. The effect is a hemisphere of sepcon message units expanding away from the surface of the sepcon disk. As the hemisphere expands the surface area increases while the size of each unit remains the same, so gaps appear between the message units. Each empty space unit is surrounded by many occupied message units. All the surrounding message units will contribute equally to creating a new message unit to fill the empty space unit. And the new message unit has the same strength of force as all the other message units. Each old message unit contributing to the creation of a new message unit has its strength reduced by a proportionate amount each time. If the strength of the new message unit is S then each of the N old message unit has its strength reduced by S/N.
At the beginning the force is directed up through the north pole or latitude 90 degrees north. Each time a sepcon message unit is split by a small amount it will direct its force slightly to a lower latitude. So that the force is successively directed toward latitude 89 degrees north, 88 degrees north, etc. until it reaches 0 degree north or the equator just as the strength of the force is reduced by exactly half. At this time the sepcon message unit would be at r2=2 and at the outer edge of sphere S2 or at the outer edge of the repulsive region R1.
The force is also directed in the Longitude 90 degrees east direction with the longitude of the point of impact being 0 degree. After reaching r2=2, the sepcon message unit would be in the A1 region where the force becomes attractive as it is directed in the downward or inward or southward direction. The force will begin by being directed straight down in the direction of the south pole. Then it is successively directed toward Latitude 89 degrees south and Longitude 90 degrees east, Latitude 88 degrees south and Longitude 90 degrees east, etc. until it reaches Latitude 0 degree or equator and Longitude 90 degrees east. Then the sepcon unit would be at the beginning of the next repulsive region, R2, where the force would start by being directed straight up through the north pole again and then systematically down toward the equator. And the cycle repeats as the sepcon message unit moves further outward away from the surface of the sepcon passing successively through repulsive region followed by attractive region followed by repulsive region, etc.
If the strength of the force is 1 at the surface of the sepcon where the surface of the sepcon is located at r=2^0.5 (square root of 2), then the total force integrated over the distance from r=2^0.5 to r=2 or the repulsive region R1 is 0.4142. But the sum of the forces in the outward direction (integrating with the sine of the force) equals 0.288. That is, the total repulsive force of the R1 region is 0.288. Similarly the total attractive force of the A1 region is 0.20365. Also the total repulsive force from radius=1.50482 to radius=2 is also 0.20365.
Assuming the proton is at x=2 at the moment when the sepcon is formed, it would be at the outer edge of R1. As the proton moves inward it would experience a repulsive force against it in the direction of Latitude 0 degree north/Longitude 90 degree east, then Latitude 1 degree north/Longitude 90 degree east, etc. If the proton is stopped in its inward direction before reaching X=1.50482 (or hemisphere of radius r=1.50482) then the repulsive force generated as it is pushed outward will not be more than the total attractive force of the A1 region. This means that the proton will be stopped before it reaches the outer edge of the A1 region at X=2.8284 (2^0.5^3) (or hemisphere of radius r=2.8284) and be pushed back in toward the surface of the sepcon again. In this way the proton will oscillate between the regions R1 and A1 forever.
As the proton is oscillating between R1 and A1 on one side of the sepcon, the electron is oscillating on the other side of the sepcon in an analogous manner. And so the sepcon is observed to be an effective separator and connector that keeps the proton and electron separated on either side of the sepcon while preventing them from flying apart.
But there is a lateral component to the forces applied to the proton matter units due to the force being applied to the Longitude 90 degrees east. These lateral forces make the proton move in a clockwise direction looking down from the north pole. As the proton spins sideways on one side and the electron spins sideways on the other side it will make the sepcon spin, wobble and roll as it tries to maintain its position at the center of the line joining the proton and the electron. Therefore, the situation becomes very dynamic and unstable. Ultimately, the proton and electron will become so unmanageable that they fly apart and the neutron is disintegrated. The mean lifetime of the neutron has been observed to be some 881 seconds.
After the proton and electron flew apart, the sepcon disk can no longer retain its shape and size because its temporary matter units depend on a constant stream of various types of message units from the proton and electron to provide the essential data to form and maintain a coordinated structure. Nevertheless, the temporary matter units of the sepcon disk must have incorporated some essential elements from the proton and electron message units into its own temporary matter units. So after some adjustments after the proton and electron had departed the sepcon disk becomes a neutrino which is found at the dissolution of the neutron into proton and electron.
While I talk about forces being applied, I donít mean that sepcon force message units actually bumped proton or electron matter units like billiard balls colliding together and transferring energy to each other as physicists believe. The sepcon message units and proton or electron matter units occupy the same space units and messages or data are transmitted from the sepcon message units to the proton or electron matter units telling them which way to move and by how much. There is no transfer of energy but only data. The energy is ultimately provided by the space units when it moves various kinds of units, message units and matter units, from one space unit to another adjoining space units. The message units and matter units are only unique states of the space units. Perhaps there really isnít anything called energy in the universe because it may not take any energy to transmit a unique state of a space unit to some adjoining space unit or units. At least not in the sense physicists mean such as heat, light, momentum, etc.
Physicists say atomic nuclei are composed of protons and neutrons. I think there are no neutrons inside the nucleus at normal times. Normally there are only protons and electrons kept together in a stable system by sepcons. Some might reasonably ask how can the sepcons keep the protons and electrons in the nuclei from flying apart when they obviously cannot keep protons and electrons connected in neutrons. This is because in the neutron there is only one sepcon for each proton and electron while in the nucleus there are 2 or more sepcons acting on each proton and electron thus cancelling out the lateral forces. Without the destabilizing lateral forces the protons and electron will oscillate up and down between the repulsive and attractive regions. I will explain further in the next part how more than one sepcon will cancel out the lateral forces.