Author: Liang2a
Date: 05-06-12 00:04
Liang’s Theory of Everything.
Part 4: What are forces?
Gravity.
Physicists think gravitational force is controlled by space and distance. I think gravitational force is controlled by the splitting of the gravity messenger units. That is, by the number of times a gravity messenger unit has split since its creation by its originator matter unit. To prove this I will first demonstrate there is an equivalence between the distance and the surface area of the gravitational sphere, that is, the sphere that is at a distance r from the center of the gravitational source. In demonstrating this I would have proven that gravitational force is a function of the surface area. Then I will demonstrate that the surface area of a gravitational sphere is a function of the number of times the gravity messenger units have split thus proving the gravitational force is a function of the number of times a gravity messenger unit has split.
It has been determined by experimental results that gravitational force is inversely proportional to the square of the distance.
G2 = G1 / d^2
Where G2 represents gravitational force at a distance r2 from the origin of the gravitational force; G1 represents a known gravitational force at a certain distance r1 from the origin of the gravitational force; d represents the ratio of r2/r1.
G2 = G1 / d^2 = G1 / (r2/r1)^2
For example, if r2/r1 is 2 then d^2 is 4 and the gravitational force at r2 is ¼ of G1.
The surface area of a sphere is calculated by the following equation:
S = 4 pi r^2
Where S represents the surface area of the sphere; pi is the ratio of a circle's circumference to its diameter; and r is the distance from the center of the sphere to the surface. If the surface area of the sphere is increased k times then r is increased square root of k times.
S2 = 4 pi (r2^2)
S1 = 4 pi (r1^2)
S2 = k S1
4 pi (r2^2) = k 4 pi (r1^2)
r2^2 = k (r1^2)
r2 = (square root of k) r1
r2/r1 = (square root of k)
But d = r2/r1, therefore,
d = (square root of k).
But as we have seen from the equation to compute the strength of the gravitational force r2/r1 is equal to d. From this we can write the equation for gravitational force as
G2 = G1 / d^2
G2 = G1 / (r2/r1)^2
G2 = G1 / (square root of k)^2
G2 = G1 / k
It is immediately clear that the gravitational force is inversely proportional to the surface area of the gravitational sphere. This means that if the surface area of the gravitational sphere is doubled then the gravitational force is halved; and if the surface area of the gravitational sphere is quadrupled then the gravitational force is quartered. Generally this means if the surface area of the gravitational sphere is increased k times then the gravitational force is reduced to 1/k with respect to the reference point. Putting it in another way, the gravitational force is inversely proportional to the surface area. That is, the gravitational force is a function of the surface area.
Next I will demonstrate the surface area of a gravitational sphere is a function of the number of times the gravity messenger units have split.
Imagine each of the matter units of a particle simultaneously project a messenger unit outward. As the messenger units begin to move away from the particle it would look like a balloon inflating. As the balloon inflates the surface area would increase and there would appear gaps between the space units inhabited by the gravity messenger units as each gravity messenger unit inhabits only one space unit at one time and the area covered by each space unit remains 1 sq. unit without change. As each messenger unit moves forward it would test the space units neighboring the space unit it is currently inhabiting to see if they are occupied by other messenger units. If not then it would split and project a copy of itself into any uninhabited space unit. In other words, each time a gravity messenger unit split it will end up with 2 copies of itself. Before splitting a messenger unit would increment a counter to record the number of splits it has undergone so that both resultant copies would register the same number of splits.
If the splitting of any one gravity messenger unit results in 2 gravity messenger units it immediately follows that if all the gravity messenger units split then the total number of gravity units would double. This means the total surface area of the gravity sphere would double. From this I have derived the following equation:
S = S0 2^n
Where S is the surface area; S0 is the surface area of the first layer of gravity messenger units as they stand on the matter units that created them; n is the number of times each gravity messenger unit has split. This means the surface area of the first layer is S0 since n is 0 because no gravity messenger unit has split at this time. After all the gravity messenger units have split once, n is equal to 1 and the surface area is doubled. And whenever all the gravity messenger units have split one more time, n is incremented by 1 and the total surface area is doubled. Since this is true for n equal to 0, n equal to 1, and if it is true for any n then it is also true for n + 1, therefore it must be true for all real number n. This proves that the surface area of the gravitational sphere is a function of n which is the number of times all the gravity messenger units have split.
I have proven above that
G = G1 / k
Where k is the multiple of surface area associated with G1. This equation means that if k is 2 then the surface area is doubled and the gravitational force is halved. If k is 4 then the surface area is quadrupled and the gravitational force is quartered. In fact we can replace k with 2^n so that if k = 2, then n = 1; if k = 4 then n = 2, etc. For example, if k = 7 then n = 2.81. This is the same as
(2^2) x (2^0.81) = 4 x 1.7411 = 7
The above means all the gravity messenger units have undergone 2 splits and 74.11% of them have undergone a third split. Therefore, we can finally write the equation of the gravitational force as a function of the number of splits:
G = G0 / 2^n.
We see that this is true for n = 0 when each gravity messenger unit is at its full strength; it is true for n = 1 then all the messenger units have undergone 1 split and the gravitational strength is reduced by half. It is also true for any n + 1 because whenever all the gravity messenger units split one more time the gravitational force is reduced by half. This proves gravitational force is a function of the number of splits of the gravity messenger units where the gravitational strength is reduced by half for each time the gravity messenger unit is split.
Each gravity messenger unit carries with it a direction pointer which points the way the unit moves. Whenever a gravity messenger unit encounters a matter unit it would interact with it by changing its direction by pivoting the direction pointer of the matter unit to the direction from which the gravity messenger unit is coming from. For example, if the matter unit is moving to the east and the gravity messenger unit is moving to the north then the direction pointer of the matter unit is pivoted to the south by a degree depending on the strength of the gravitational force as indicated by the number of splits the gravity messenger unit has undergone.
The gravitational strength of a gravity messenger unit also affects the number of steps a matter unit will advance during any period. The number is increased or decreased depending on the angle between the direction pointer of the gravity messenger unit and the direction pointer of the matter unit.
Since the gravity messenger units only carry information to update the data of the matter units. These data have no effect on the space units through which they pass. Therefore, it is unlikely if not impossible for them to change the structure of the space units. In other words, it is impossible for gravity to warp space.
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